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We ll start with the following simple function that is, in principle, meant to return true if the input string is a palindrome and false otherwise: let isPalindrome (str:string) = let rec check(s:int, e:int) = if s = e then true elif str.[s] <> str.[e] then false else check(s + 1, e - 1) check(0, str.Length - 1)

for (var i=0;i<100;i++){ var divisor=i-57; debugger; var val=42/divisor; plotOnGraph(i,val); }

The function appears correct at first sight. However, it works only for strings with an odd number of characters and strings with an even length that are not palindromes. In particular, the program raises an exception with the "abba" string as input. We ll show how to use the Visual Studio debugger to figure out the problem with this simple function. The algorithm recursively tests the characters of the string pair-wise at the beginning and at the end of the string because a string is a palindrome if the first and last characters are equal and the substring obtained by removing them is a palindrome too. The s and e variables define the boundaries of the string to be tested and initially refer to the first and last characters of the input string. Recursion terminates when the outermost characters of the string to be tested differ or when you have tested the whole string and the indexes collide. Figure 18-1 shows the debugging session of the simple program. You set a breakpoint at the instruction that prints the result of the isPalindrome function for the "abba" string by clicking where the red circle is shown, which indicates the location of the breakpoint. When the program is started in debug mode, its execution stops at the breakpoint, and you can step through the statements. The current instruction is indicated by the yellow arrow, and the current statement is highlighted, as shown in Figure 18-1.

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but we would need to click the resume button on our debugger numerous times to step through the loop to the point where we encounter the error condition. If we re being clever, we can test for the error condition in our code:

s Note If you do not see the Developer tab, see the sidebar in section 7.1 to learn how to display it.

for (var i=0;i<100;i++){ var divisor=i-57; if (divisor==0){ debugger; } var val=42/divisor; plotOnGraph(i,val); }

Figure 18-1. The Visual Studio debugger The state of the program is accessible through a number of windows showing different aspects of the running program, usually docked at the bottom of the debugging window. It is possible, for instance, to inspect the state of the local variables of the current method (the Locals window showing the local variables and arguments, e and s in this example) or the state of the call stack to see the sequence of method calls (the Call Stack window). An important window is the Watch view, which can be used to write variable names and simple expressions and watch them change during the execution. It is also possible to evaluate expressions in the Immediate

This will take us straight to the fifty-seventh iteration of the loop, the one at which our error condition occurs. We could describe this as a conditional breakpoint that is, it will break the flow of execution only if a certain condition is met. We can set up conditions in this way only by modifying the code. However, if we are assigning breakpoints through the debugger IDE, we can set a condition on the breakpoint independently of the actual code (figure A.7). Some debuggers do support this facility, allowing the user to attach expressions to a breakpoint, and break the flow only if the expression evaluates to true. Changing the values of variables If we encounter an error condition, our program execution halts. In a debugging session, we may realize what the solution is but want to coerce the program into continuing anyway, in order to test some later piece of code under the current set of conditions.

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